HRS - Ask. Learn. Share Knowledge. Logo

In Mathematics / High School | 2014-04-22

Solve for \( n \) in the equation:

\[ p = 3n + 3u \]

Asked by alanizroman

Answer (3)

p = 3 n + 3 u 3 n + 3 u = p / − 3 u 3 n + 3 u − 3 u = p − 3 u 3 n = p − 3 u / : 3 3 n : 3 = ( p − 3 u ) : 3 = 3 p − 3 u ​ → n = 3 p ​ − 3 3 u ​ → n = 3 1 ​ p − u

Answered by Anonymous | 2024-06-10

3n=3u+p n=3u+p/3
dont read under here .... uhdusbsacucuabcuabcjaSCC CS s c sc sc scacac adc dch dv uvb sasc dv d dac d d d c cs cas

Answered by vughbhbyg | 2024-06-10

To solve for n in the equation p = 3 n + 3 u , isolate n by subtracting 3 u from both sides and then dividing by 3. The solution is n = 3 p − 3 u ​ or simplified as n = 3 p ​ − u .
;

Answered by Anonymous | 2024-11-02