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In Mathematics / High School | 2014-04-22

How do you solve this rational equation?

\[
\frac{4}{3(c+4)} + 1 = \frac{2c}{c+4}
\]

Asked by Hellokitty593

Answer (2)

4/3(c+4) + 1 = 2c/c+4 , where c is not -4 <=> 4 / [3(c + 4)] + 3( c + 4) /[ 3( c + 4)] = 6c / [3( c + 4)] <=> 4 + 3c + 12 = 6c <=> 16 = 3c <=> c = 16 / 3.

Answered by crisforp | 2024-06-10

To solve the equation 3 ( c + 4 ) 4 ​ + 1 = c + 4 2 c ​ , first eliminate the fractions by multiplying by the common denominator. After simplifying and isolating c , you find that the solution is c = 3 16 ​ .
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Answered by crisforp | 2024-12-23

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