If [tex]\sin \alpha = \frac{12}{13}[/tex] and [tex]\cos \alpha = \frac{5}{13}[/tex], then what is [tex]\tan \alpha[/tex]?

s in α = 13 12 ​ cos α = 13 5 ​ t an α = cos α s in α ​ t an α = 13 12 ​ : 13 5 ​ = 13 12 ​ ⋅ 5 13 ​ = 5 12 ​ = 2 5 2 ​ = 2.4

Answered by Anonymous | 2024-06-10

If you draw a right angles triangle you can fill in the values. So since sinx= opposite/hypotenuse then the hypotenuse of the triangle is 13. And the side opposite the angle a is 12. Since cosx= adjacent/ hypotenuse, the adjacent side is 5. Tanx=opposite/adjacent and therefore tana= 12/5

Answered by eilidhgreen | 2024-06-10

The value of \(\tan \theta \) is \(\frac{12}{5} \) or 2.4. This is calculated by dividing \(\text{sin} \theta \) by \(\text{cos} \theta \.
;

Answered by Anonymous | 2024-10-30