Δ A BC ∼ Δ D A C t h e n ∣ BC ∣ ∣ A C ∣ = ∣ A C ∣ ∣ C D ∣ ∣ A C ∣ 2 = ∣ BC ∣ ⋅ ∣ C D ∣ ∣ A C ∣ 2 = 4 ⋅ 27 ∣ A C ∣ = 4 ⋅ 27 ∣ A C ∣ = 4 ⋅ 27 ∣ A C ∣ = 2 ⋅ 9 ⋅ 3 ∣ A C ∣ = 2 9 ⋅ 3 ∣ A C ∣ = 2 ⋅ 3 3 ∣ A C ∣ = 6 3
31 is the answer I think..
The length of AC, given that BC = 4 and CD = 27, is found using the formula A C 2 = BC ⋅ C D . After calculating, we find A C = 6 3 . This demonstrates the relationship between the segments on the line.
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