If BC = 8.3, CD = 6.7, and AD = 11.6, find AB to the nearest tenth.

The length of AB to the nearest tenth is 14.2 units.
Given that:

BC = 8.3

CD = 6.7

AD = 11.6


We want to find the length of (AB).
Let's use the property of a circumscribed quadrilateral (a quadrilateral that touches a circle at its vertices) to solve this problem.

Property:

- In a circumscribed quadrilateral, the sum of opposite sides is equal.
- Specifically, for our quadrilateral ABCD:
AB + CD = AD + BC

Substitute the given values:

AB + 6.7 = 11.6 + 8.3

Solve for AB:

AB = (11.6 + 8.3) - 6.7 = 20.9 - 6.7 = 14.2

Rounded to the nearest tenth:

- The length of AB is approximately 14.2 units.
Therefore, the length of AB to the nearest tenth is 14.2 units.

Answered by ritumandalira | 2024-06-24

Answer: 12.6
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Answered by shawndaleberry28 | 2024-06-24

The length of segment AB is 13.2 units, calculated using the property of circumscribed quadrilaterals. By applying the formula for opposite sides, we find that AB + CD equals AD + BC. After substituting the values and solving, we conclude that AB is 13.2 units long.
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Answered by ritumandalira | 2024-11-18