Solve \( 8m^2 + 20m = 12 \) for \( m \) by factoring.

Please show all work.

8 m 2 + 20 m = 12/ : 2 4 m 2 + 10 m = 6 4 m 2 + 10 m − 6 = 0 Δ = b 2 − 4 a c Δ = 100 − ( 4 ∗ 4 ∗ − 6 ) Δ = 100 + 96 = 196 x 1 = 8 − b − Δ ​ ​ x 1 = 8 − 10 − 14 ​ x 1 = 8 − 24 ​ x 1 = − 3 x 1 = 8 − b + Δ ​ ​ x 2 = 8 − 10 + 14 ​ x 2 = 2 1 ​
so you can write 8 m 2 + 20 m = 12/ : 2 as
8 ( m + 3 ) ( m − 2 1 ​ ) = 8 ∗ [ m 2 + 2.5 m − 1.5 ] = 0

Answered by mackiemesser | 2024-06-10

To solve 8 m 2 + 20 m = 12 by factoring, we rewrote it as 2 m 2 + 5 m − 3 = 0 and factored it as ( 2 m − 1 ) ( m + 3 ) = 0 . This gives the solutions m = 2 1 ​ and m = − 3 .
;

Answered by mackiemesser | 2025-02-01