Use substitution to solve the system:

\[ 5x - 3y = -20 \]
\[ x = 3y - 16 \]

5 x − 3 y = − 20 x = 3 y − 16
Plug in 'x' into the first equation:
5 ( 3 y − 16 ) − 3 y = 20 15 y − 80 − 3 y = − 20 12 y = 60 y = 5
Plug in 'y' into the second equation to get 'x':
x = 3 y − 16 x = 3 ( 5 ) − 16 To get x = − 1
y = 5 x = − 1

Answered by xlmichael | 2024-06-10

5(3y-16)-3y = -20 15y-80-3y = -20 12y = 60 y = 5

Answered by brainlydotcom | 2024-06-10

By using substitution, we solved the system of equations and found that x = − 1 and y = 5 . We substituted the expression for x into the first equation, solved for y, and then back-substituted to find x. The confirmed solution satisfies both original equations.
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Answered by xlmichael | 2024-12-17