Find the 50th term of this arithmetic sequence: 5, 13, 21, 29, ...

Step 1. The constant for this sequence is 4 since 5-1=4 and 9-5=4.
Step 2. Using this constant, we have 1+(n-1)*4 as the formula. We can check with n=1 or 1+(1-1)*4=1. With n=2, 1+(2-1)*4=5. With n=3, 1+(3-1)4=9. So it checks out.
Step 3. With n=50, then 1+(50-1)*4=197. Step 4. ANSWER: The 50th term is 197.
I hope the above steps were helpful.

Answered by phninse | 2024-06-10

To find the 50th term of the arithmetic sequence 5, 13, 21, 29, you identify the first term as 5 and the common difference as 8. Using the formula for the nth term, T_n = a + (n - 1) * d, the 50th term is calculated as 397. Thus, the 50th term is 397.
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Answered by phninse | 2024-12-16