There are 376 stones in three piles. The second pile has 24 more stones than the first. The third pile has twice as many stones as the second.

How many stones are in each pile?

Let the stones of each piles be x, y and z respectively.
thus, x + y + z = 376
x=x y = x + 24 z= 2y = 2(x+24)
This becomes x + x + 24 + 2(x+24) = 376
= 4x + 24 + 48 = 376
= 4x + 72 = 376
Thus, 4x = 304
Thus, x = 76
and y = 76 + 24 = 100
and z = 2 x 100 = 200
Thus, first pile has 76 stones, second pile has 100 stones and third pile has 200 stones

Answered by tadvisohil886 | 2024-06-24

The first pile has 76 stones, the second pile has 100 stones, and the third pile has 200 stones. This is based on a set of equations derived from the relationships between the piles. The total number of stones adds up to 376.
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Answered by tadvisohil886 | 2024-12-23