Geometry
The diagonals of a kite are in the ratio of 3:2. The area of the kite is [tex]27 \, \text{cm}^2[/tex]. Find the length of both diagonals.
Hint: Let the lengths of the diagonals be [tex]3x[/tex] and [tex]2x[/tex].
Answer (2)
A = 27 c m 2 d 1 = 3 x , d 2 = 2 x S = 2 1 ⋅ d 1 ⋅ d 2 27 = 2 1 ⋅ 3 x ⋅ 2 x 3 x 2 = 27 / : 3
x 2 = 9 3 x = x = 9 x = 3 c m d 1 = 3 x = 3 ∗ 3 = 9 c m d 2 = 2 x = 2 ∗ 3 = 6 c m A n s w er : T h e l e n g t h o f t h e d ia g o na l i s : d 1 = 9 c m an d d 2 = 6 c m
The lengths of the diagonals of the kite are 9 cm and 6 cm. This is derived from their ratio and the given area of the kite. By solving for the value of x , we find each diagonal's length.
;
