I'm assuming x2 means x^2, so the polynomial is unable to be factored so you plug it into the quadratic formula. (-b+/- sqr(4ac-a^2))/2a. Once you do this your final product is positive/negative 7/9
Since 2x and 5x have the same variable u have to add them 2x + 5x = 7x + 9 7x + 9 will be the answer
The polynomial x 2 + 5 x + 9 does not have real roots, as its discriminant is negative. The roots are complex and given by x 1 = 2 − 5 + i 11 and x 2 = 2 − 5 − i 11 .
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