Solve for \( x \).

\(\log x + \log 8 = 2\)

To start we will use the sum to product rule of logs to make logx + log 8 = 2 -> log8x = 2. now assuming that this is log base 10 we will get rid of the log by raising both sides to the power of ten.
8x = 10^2 8x = 100 x = 100/8

Answered by brad96pop | 2024-06-10

The solution to the equation l o g ( x ) + l o g ( 8 ) = 2 is x = 12.5 .
To solve the equation log(x) + log(8) = 2, we can use the properties of logarithms.
The equation can be simplified using the logarithmic property :
l o g ( a ) + l o g ( b ) = l o g ( ab )
l o g ( x ) + l o g ( 8 ) = 2
l o g ( 8 x ) = 2
Rewrite the equation in exponential form:
1 0 2 = 8 x
100 = 8 x
To solve for x, divide both sides of the equation by 8:
8 100 ​ = x
12.5 = x
Therefore, the solution to the equation l o g ( x ) + l o g ( 8 ) = 2 is x = 12.5 .
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Answered by pukhrajvt | 2024-06-17

To solve lo g x + lo g 8 = 2 , combine the logs to get lo g ( 8 x ) = 2 and convert it to exponential form, yielding 8 x = 100 . Dividing both sides by 8 gives x = 12.5 .
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Answered by brad96pop | 2024-12-23