What is the remainder of \((6x^3) \div (x+2)\)?

6 x 3 : ( x + 2 ) w ( x ) = 6 x 3 re main d er o f 6 x 2 : ( x + 2 ) e q u a l w ( − 2 ) w ( − 2 ) = 6 ⋅ ( − 2 ) 3 = 6 ⋅ ( − 8 ) = − 48 ← an s w er

Answered by Anonymous | 2024-06-10

The remainder of ( 6 x 3 ) ÷ ( x + 2 ) is − 48 using the Remainder Theorem, which involves evaluating the polynomial at x = − 2 . The calculation shows that 6 ( − 2 ) 3 = − 48 .
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Answered by Anonymous | 2024-12-20