A rectangle has an area of 30 square units and a perimeter of 34 meters. What are the dimensions of this rectangle?

P = 2 L + 2 W A = W L
Therefore, if P = 34 , and A = 30 , then let us find the factors of 30 that could give a sum of half of the perimeter which is 34. Therefore:
P = 2 ∗ 15 + 2 ∗ 2 A = 15 ∗ 2
P = 34 A = 30
Therefore, the dimensions of this rectangle are 15 and 2.

Answered by Edmund | 2024-06-10

The dimensions of the rectangle are 15 meters and 2 meters, found using the formulas for perimeter and area. By solving the simultaneous equations derived from these formulas, we determined the length and width. The calculations led us to the two pairs (15, 2) or (2, 15), which represent the same rectangle.
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Answered by Edmund | 2024-12-20