x = 11 , A ( 11 , 0 ) x = 5 , B ( 5 , 0 ) d i s t an ce b e tw ee n tw o p a r a ll e l l in es : d = ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 d = ( 5 − 11 ) 2 + ( 0 − 0 ) 2 = ( − 6 ) 2 = 36 = 6
T h e d i s t an ce : d = ∣11 − 5∣ = ∣6∣ = 6
The distance between the parallel lines x = 11 and x = 5 is 6 units. This is calculated by using the formula for the distance between two vertical lines. By determining the absolute difference of their x-values, we find the distance to be 6.
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