3 ∗ 2 ∗ 1 32 ∗ 31 ∗ 30
The answer is: 6 29760 or 4960
( 3 32 ) = 3 ! ∗ ( 32 − 3 )! 32 ! = 6 30 ∗ 31 ∗ 32 = 4960
The number of combinations of 3 students that can be chosen from 32 students is 4,960. Therefore, the correct answer is B. 4,960.
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