A bottle rocket made in science class had a trajectory path that followed the quadratic equation [tex]y = -x^2 + 4x + 6[/tex]. What is the turning point of the rocket's path?

1) (1, 5)
2) (2, 10)
3) (-2, -10)
4) (1, -5)

y = − x 2 + 4 x + 6 a = − 1 , b = 4 , c = 6 T h e v er t e x i s ( x , f ( x )) x = 2 a − b ​ = 2 ⋅ ( − 1 ) − 4 ​ = − 2 − 4 ​ = 2 f ( 2 ) = − x 2 + 4 x + 6 = − 2 2 + 4 ⋅ 2 + 6 = − 4 + 8 + 6 = 10 T h e v er t e x i s ( 2 , 10 ) A n s w er : 2 ) ( 2 , 10 )

Answered by Lilith | 2024-06-10

The turning point of the rocket's path described by the quadratic equation y = − x 2 + 4 x + 6 is ( 2 , 10 ) . Therefore, the correct answer is option 2) (2, 10).
;

Answered by Lilith | 2024-11-03