An oscillator makes four vibrations in one second. What are its period and frequency?

Frequency = no. of oscillations/ time
= 4 / 1 = 4Hz
Time period = 1/ frequency
= 1/ 4
= 0.25 seconds.

Answered by tadvisohil886 | 2024-06-24

If an oscillator makes four vibrations in one second, its frequency is 4 Hz, as frequency is defined as the number of oscillations per second. To find its period, which is the time for one oscillation, we use the reciprocal of the frequency. Therefore, the period T is 1 divided by the frequency f.
Using the formula f = 1/T, we can calculate the period T as 1/4 Hz, which is 0.25 seconds. Thus, the period of the oscillator is 0.25 seconds, and its frequency is 4 Hz.

Answered by qwfish | 2024-06-24

The frequency of the oscillator is 4 Hz, meaning it vibrates four times per second. The period of the oscillator is 0.25 seconds, indicating it takes a quarter second to complete one cycle. Therefore, the oscillator has a frequency of 4 Hz and a period of 0.25 seconds.
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Answered by tadvisohil886 | 2024-10-30