How do you graph the inequality [tex]4x + 3 < 7x - 9[/tex] on a number line?

4 x + 3 < 7 x − 9 ∣ − 7 x 4 x − 7 x + 3 < 7 x − 7 x − 9 − 3 x + 3 < − 9 ∣ − 3 − 3 x + 3 − 3 < − 9 − 3 − 3 x < − 12 / : ( − 3 )
\frac{-12}{-3}\\ \\ x >4"> x > − 3 − 12 ​ x > 4

Answered by Lilith | 2024-06-10

To graph the inequality 4 x + 3 < 7 x − 9 , isolate x to find that it simplifies to 4"> x > 4 . On a number line, represent this by drawing an open circle at 4 and shading to the right of this point. This visually indicates all values greater than 4 satisfy the inequality.
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Answered by Lilith | 2024-09-30