How many atoms are in 3.50 moles of calcium (Ca)?
Answer (2)
No. of atoms = no.of moles x avagadro's constant
= 3.50 x 6.022*10^23
= 21.077 x 10 ^23
To calculate the number of atoms in 3.50 moles of calcium, multiply 3.50 by Avogadro's constant (approximately 6.022 × 1 0 23 ). This gives approximately 2.11 × 1 0 24 atoms of calcium. Therefore, 3.50 moles of calcium contains around 2.11 × 1 0 24 atoms.
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