How do you solve for \(2m^2 + 2m - 12 = 0\)?

Use the quadratic formula.

The quadratic equation 2m² + 2m - 12 = 0 can be solved using the quadratic formula; the solutions are m = 2 and m = -3.
To solve the quadratic equation 2m² + 2m - 12 = 0, we can use the quadratic formula, which is x = (-b ± √(b² - 4ac)) / (2a) where a, b, and c are coefficients from the equation ax^2 + bx + c = 0.
First, identify the coefficients: a = 2, b = 2, and c = -12. Apply them to the formula:
x = (-2 ± √(2² - 4×2×(-12))) / (2×2) = (-2 ± √(4 + 96)) / 4 = (-2 ± √100) / 4 = (-2 ± 10) / 4
Now, solve for the two possible values of m:
m₁ = (-2 + 10) / 4 = 8 / 4 = 2
m₂ = (-2 - 10) / 4 = -12 / 4 = -3
The solutions to the equation 2m² + 2m - 12 = 0 are m = 2 and m = -3.

Answered by PragatiR | 2024-06-24

To solve the equation 2 m 2 + 2 m − 12 = 0 using the quadratic formula, identify the coefficients: a = 2 , b = 2 , c = − 12 . Plug these values into the formula and simplify to find that the solutions are m = 2 and m = − 3 .
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Answered by PragatiR | 2024-12-23