y = 3 2 x , ( 2 , 0 ) m = 3 2 T h e s l o p e o f l in es p a r a ll e l i s t h e s am e u se y = m x + b an d t h e p o in t ( 2 , 0 ) t o f in d b 0 = − 3 2 ⋅ 2 + b
0 = − 3 4 + b b = − 3 4 y = − 3 2 x + 3 4
To determine the standard form of the equation of a line through the point (2, 0) and parallel to y = 3 2 x , we utilized the point-slope form and transformed it into standard form. The resulting equation is 2 x − 3 y = 4 .
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