\left\{\begin{array}{ccc}x-2y=1\\x+4y=7&/\cdot(-1)\end{array}\right\\\\+\left\{\begin{array}{ccc}x-2y=1\\-x-4y=-7\end{array}\right\\-----------\\.\ \ \ \ \ \ \ \ \ -6y=-6\ \ \ \ \ /:(-6)\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ y=1\\\\x-2\cdot1=1\\x-2=1\\x=1+2\\x=3\\\\Answer:\\\left\{\begin{array}{ccc}x=3\\y=1\end{array}\right
x - 2y = 1
(-x - 4y = -7)
-6y = -6
-6 -6
We divide -6 both sides of the equation in order to get our answer.
y = 1 ;
The y-coordinate of the solution to the system of equations is 1. By substituting values and solving simultaneously, we found the point of intersection, which is (3, 1). Thus, the corresponding y-coordinate is 1.
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