#1 = 12 units
#2 = 5.1 I think
#3...
Distance between the points (4, 7) and (4, –5) is 12 units and distance between the points (–3, 5) and (2, –6) is 12.01 units.
What is Distance?
The length along a line or line segment between two points on the line or line segment.
Distance=√(x₂-x₁)²+(y₂-y₁)²
The distance between the points (4, 7) and (4, –5)
x₁=4, y₁=7, x₂=4, y₂=-5
Distance=√(x₂-x₁)²+(y₂-y₁)²
Distance=√(4-4)²+(-5-7)²
=√(-12)²
=√144
=12
Hence distance between the points (4, 7) and (4, –5) is 12 units.
the distance between the points (–3, 5) and (2, –6)
x₁=-3, y₁=5, x₂=2, y₂=-6
Distance=√(x₂-x₁)²+(y₂-y₁)²
=√(2-(-3))²+(-6-5)²
=√(5)²+(-11)²
=√25+121
=√146
=12.08
So distance between the points (–3, 5) and (2, –6) is 12.01 units.
Hence distance between the points (4, 7) and (4, –5) is 12 units and distance between the points (–3, 5) and (2, –6) is 12.01 units.
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The distance between the points (4, 7) and (4, -5) is 12 units, and for the points (-3, 5) and (2, -6), it is approximately 12.1 units. The correct answers are B for the first question and C for the second question.
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