ab + 9 = 3 b − 5 c ∣ − 3 b − 3 b + ab + 9 = 3 b − 3 b − 5 c − 3 b + ab + 9 = − 5 c ∣ − 9 − 3 b + ab + 9 − 9 = − 5 c − 9 − 3 b + ab = − 5 c − 9 / ⋅ ( − 1 ) 3 b − ab = 5 c + 9 b ( 3 − a ) = 5 c + 9 / : ( 3 − a ) b = 3 − a 5 c + 9
To solve for b in the equation ab + 9 = 3 b − 5 c , isolate b by moving terms around and factoring. The final expression for b is b = a − 3 − 5 c − 9 .
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