Scott has \(\frac{1}{3}\) of the computer games as Anish, and Anish has \(\frac{1}{2}\) as many games as Nick. Together they have 140 games. How many games do they each have?

Scott has ______

Anish has ______

Nick has ______

Scott = Anish ÷ 3 or 1/3 Anish Anish = Nick ÷ 2 or 1/2 Nick S + A + N = 140 1/6 N + 3/6 N + 6/6 N = 10/6 N (140) 10/6 N = (140) 140 ÷ 10 = 1/6 N (14) = Scott 9/6 N (126) - 3/6 (42 = Anish) = N = 84 S = 14 A = 42 N = 84
CHECK?
14 = 1/3 of 42 42 = 1/2 of 84 14 + 42 + 84 = 140 :)

Answered by Dannymal | 2024-06-10

let x = # of computer games nick has then Anish has 1/2x games and Scot has 1/2 1/3 = 1/6x games thus 1/6x + 1/2x + x = 140 1/6x + 3/6x + x = 140 10/6x = 140 10x =140 6 x = 84 > Nick 1/2x = 42 > Anish 1/6x = 14 > Scot

Answered by Poknoy | 2024-06-10

Scott has 14 games, Anish has 42 games, and Nick has 84 games. This is determined through setting up equations based on the relationships between the number of games each person has. By substituting these relationships and solving the equations, we find the number of games each individual possesses.
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Answered by Dannymal | 2024-09-27