Use the quadratic formula to solve \(2y^2 - 5y = -2\).

Possible solutions:
A. \(\{-\frac{1}{2}, 2\}\)
B. \(\{-\frac{1}{2}, -2\}\)
C. \(\{\frac{1}{2}, 2\}\)
D. \(\{\frac{1}{2}, -2\}\)

2 y 2 − 5 y = − 2 2 y 2 − 5 y + 2 = 0 a = 2 , b = − 5 , c = 2 Δ = b 2 − 4 a c = ( − 5 ) 2 − 4 ⋅ 2 ⋅ 2 = 25 − 16 = 9 y 1 ​ = 2 a − b − Δ ​ ​ = 2 ⋅ 2 5 − 9 ​ ​ = 4 5 − 3 ​ = 4 2 ​ = 2 1 ​
y 2 ​ = 2 a − b + Δ ​ ​ = 2 ⋅ 2 5 + 9 ​ ​ = 4 5 + 3 ​ = 4 8 ​ = 2 A n s w er : { 2 1 ​ , 2 }

Answered by Lilith | 2024-06-10

1/2, 2 ;

Answered by rayne1day | 2024-06-13

The solutions to the equation 2 y 2 − 5 y = − 2 are { 2 1 ​ , 2 } . The correct answer is option C. We used the quadratic formula to find the roots of the rearranged quadratic equation.
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Answered by Lilith | 2024-12-23