Solve for \( x \).
\[ -3x + 8y = 5 \]
\[ 6x - 2y = 10 \]

Let us solve this system by substitution.
-3x + 8y = 5 6x - 2y = 10
According to equation 2,
6x - 2y = 10
6x = 10 + 2y
thus, x = 10 + 2y / 6
substituting the value of x in equation 1,
-3 ( 10 + 2y / 6) + 8y = 5
-30 - 6y + 8y = 5 x 6 = 30
-30 + 2y = 30
2y = 60
Thus, y = 30.
Substituting the value of y in equation 2,
6x - 2y = 10
6x - 2(30) = 10
6x - 60 = 10
6x = 70.
Thus, x = 70/6.
Thus, x = 70 / 6 ( and y = 30)

Answered by tadvisohil886 | 2024-06-10

The value of x is 10/3
To solve for x in the system of equations given, we can use the method of elimination or substitution. The given equations are:
-3x + 8y = 5
6x - 2y = 10
The first step is to remove one of the variables. We can do this by multiplying the first equation by 2 and the second equation by 3, to get equal coefficients for y:
-6x + 16y = 10
18x - 6y = 30
Add these modified equations together:
12x = 40
Now divide both sides by 12 to solve for x:
x = 40 / 12
x = 10 / 3
We have found the value of x to be 10/3. To find y , substitute x back into one of the original equations.

Answered by SumeraAshfaq | 2024-06-24

To solve the given system of equations, we substituted to find that x = 7 15 ​ and y = 7 10 ​ . Through manipulation of the equations, both values were derived successfully. This method effectively demonstrated the steps to arrive at the solution.
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Answered by tadvisohil886 | 2024-12-26