− 3 x 2 y ∗ ( 5 x y 2 + x y ) = = − 3 x 2 y ⋅ 5 x y 2 − 3 x 2 y ⋅ x y = = − 3 ⋅ 5 x 2 + 1 y 1 + 2 − 3 x 2 + 1 y 1 + 1 = = − 15 x 3 y 3 − 3 x 3 y 2
The product of − 3 x 2 y and ( 5 x y 2 + x y ) can be calculated by distributing − 3 x 2 y over each term in the binomial. This leads to -15x³y³ - 3x³y². Thus, the final product is − 15 x 3 y 3 − 3 x 3 y 2 .
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