27=3x-5+x 27+5=4x-5+5 4x=32 4x/4=32/4 x=8 There are 8 blue marbles and 19 red marbles.
Let
x--------> The number of red marbles
y--------> The number of blue marbles
we know that
x + y = 27 x = 27 − y
equation 1
x = 3 y − 5
equation 2
equate equation 1 and equation 2
27 − y = 3 y − 5 3 y + y = 27 + 5 4 y = 32 y = 8
x = 3 ∗ 8 − 5 x = 19
therefore
the answer is
The number of red marbles is 19
The number of blue marbles is 8
There are 19 red marbles and 8 blue marbles in the bag. This is found by solving the equations based on the relationships given in the problem. The total number of marbles adds up to 27, meeting the conditions stated.
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