925 ÷ 8 9 ÷ 8 = 1 r1 put 1 before the 2 = 12 12 ÷ 8 = 1 r 4 4 before 5 = 45 45 ÷ 8 = 5 r 5 So it's 115 r 5
115 and 5/8 refered
925 divided by 8 results in 115 with a remainder of 5, or mathematically expressed as 115 R 5. This is found by performing long division. Each step involves determining how many times 8 fits into parts of 925 sequentially until all digits are used.
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