Factor completely: $4u^2 + 28u + 49$

Question

kate200468 · Answer

4 u 2 + 28 u + 49 = 4 u 2 + 14 u + 14 u + 49 = 2 u ( u + 7 ) + 7 ( u + 7 ) = = ( u + 7 ) ( 2 u + 7 )

jnvkr1 · Answer

Answer: (2u + 7)^2 ;

kate200468 · Answer

The expression 4 u 2 + 28 u + 49 can be factored completely as ( 2 u + 7 ) 2 , indicating that it is a perfect square trinomial. Each step shows the process of identifying the factors through recognizing the perfect square form. This completes the factorization of the original quadratic expression. 
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Factor completely: \(4u^2 + 28u + 49\)

Answer (3)

Factor completely: \(4u^2 + 28u + 49\)

Answer (3)

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