Use long division to solve:

\[(30x^3 + 4x^2 - 150) \div (3x - 5)\]

30 x 3 + 4 x 2 − 150 = 10 x 2 ( 3 x − 5 ) + 18 x ( 3 x − 5 ) + 30 ( 3 x − 5 ) = = ( 3 x − 5 ) ( 10 x 2 + 18 x + 30 ) ( 30 x 3 + 4 x 2 − 150 ) : ( 3 x − 5 ) = 3 x − 5 ( 3 x − 5 ) ( 10 x 2 + 18 x + 30 ) ​ = 10 x 2 + 18 x + 30

Answered by kate200468 | 2024-06-10

Using long division, the result of ( 30 x 3 + 4 x 2 − 150 ) ÷ ( 3 x − 5 ) is 10 x 2 + 18 x + 30 with no remainder.
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Answered by kate200468 | 2024-12-24