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In Mathematics / High School | 2014-05-14

What is the volume of a circular mine passage that is 19.0 feet in diameter and 210.0 feet long?

Asked by Dun166

Answer (2)

d = d iam e t er : d = 19 f t r a d i u s : r = 2 d ​ = 2 19 ​ = 9.5 f t l e n g t h o f o bj ec t : h = 210 f t C i rc l e A re a : A = π r 2 C i rc u l a r V o l u m e = A ∗ h = π r 2 h C i rc u l a r V o l u m e = π ⋅ 9 , 5 2 ∗ 210 = 90 , 25 ⋅ 210 ⋅ π = 18952.5 π f t 3

Answered by Lilith | 2024-06-10

The volume of the circular mine passage is approximately 59542.3 cubic feet. This was calculated using the formula for the volume of a cylinder, considering the diameter and length of the passage. The exact volume can also be expressed as 18952.5π cubic feet.
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Answered by Lilith | 2024-12-23

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