Solve for [tex]m[/tex] in [tex]E = \frac{1}{2}mv^2 + mgh[/tex].

E = 2 1 ​ m v 2 + m g h / ⋅ 2 2 ⋅ 2 1 ​ m v 2 + 2 \cdotmgh = 2 ⋅ E m v 2 + 2 m g h = 2 E m ( v 2 + 2 g h ) = 2 E m = v 2 + 2 g h 2 E ​

Answered by Lilith | 2024-06-10

E = 2 1 ​ m v 2 + m g h / ⋅ 2 2 E = m v 2 + 2 m g h 2 E = m ( v 2 + 2 g h ) / : ( v 2 + 2 g h ) m = v 2 + 2 g h 2 E ​

Answered by kate200468 | 2024-06-24

To solve for m in the equation E = 2 1 ​ m v 2 + m g h , isolate m to get m = v 2 + 2 g h 2 E ​ . This allows you to calculate the mass when the values of energy, velocity, and height are known.
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Answered by Lilith | 2024-08-26