Rewrite the expression by using grouping symbols:
\[ y \cdot 4 + y \cdot z \]
A. \( 4(y + z) \)
B. \( y \cdot (4 + y) \cdot z \)
C. \( z(y \cdot 4) \)
D. \( y(4 + z) \)
Answer (2)
y ⋅ 4 + y ⋅ z = y ⋅ ( 4 + z ) ⇒ A n s . D
The expression y ⋅ 4 + y ⋅ z can be rewritten as y ( 4 + z ) by factoring out the common factor y . The correct answer is option D, y ( 4 + z ) .
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