SOLVING SYSTEMS OF EQUATIONS BY ELIMINATION:

\[
\begin{aligned}
-4x - 2y &= -12 \\
4x + 8y &= -24
\end{aligned}
\]

-4x-2y=-12 4x+8y=-24
Cancel out the x 6y=-36 Divide both sides by 6 y=-6
Substitute the value of y to any equation -4x-2y=-12 -4x-2[-6]=-12 -4x+12=-12 -4x=-24 Divide both sides by -4 x=6

Answered by HunterX | 2024-06-10

Your going to add the two equations to cancel out the x term. You get 6y=-36. Divide both sides by 6 and you get y=-6. Plug y in in your first equation and you'll get -4x-2(-6)=-12. Multiply the -2 by the -6 and you'll get -4x+12=-12. Subtract 12 from both sides and you get -4x=-24. Divide both sides by -4 and you get x=6. Your final answer is x=6, y=-6.

Answered by dabobman | 2024-06-24

To solve the system of equations, we first align the two equations and then eliminate one variable by manipulating the equations. We found that x = 6 and y = -6 by substituting and simplifying. Thus, the solution to the system is (6, -6).
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Answered by dabobman | 2024-08-28