A student sells small and large greeting cards at a craft fair. The small cards cost $3 per card, and the large cards cost $5 per card. The student collects $95 for selling a total of 25 cards.

1. What are the variables?
2. What is the system of equations?
3. How do you graph it?
4. How many of each type of card did the student sell?

x-the\ small\ cards\\y-the\ large\ cards\\\\ \left\{\begin{array}{ccc}3x+5y=95\\x+y=25\end{array}\right\\\left\{\begin{array}{ccc}5y=-3x+95&/:5\\y=-x+25\end{array}\right\\\left\{\begin{array}{ccc}y=-\frac{3}{5}x+19\\y=-x+25\end{array}\right\\\\----------------------
y = − 5 3 ​ x + 19 f or x = 0 → y = − 5 3 ​ ⋅ 0 + 19 = 19 → A ( 0 ; 19 ) f or x = 10 → y = − 5 3 ​ ⋅ 10 + 19 = − 6 + 19 = 13 → B ( 10 ; 13 ) − − − − − − − − − − − − − − − − − − − − − − − − − − − − y = − x + 25 f or x = 0 → y = − 0 + 25 = 25 → C ( 0 ; 25 ) f or x = 10 → y = − 10 + 25 = 15 → D ( 10 ; 15 ) − − − − − − − − − − − − − − − − − − − − − − − − − − − − a g r a p h o n t h e p i c t u re A n s w er : x = 15 an d y = 10.

Answered by Anonymous | 2024-06-10

15 small and 10 big cards to the days if you want to.

Answered by danyaltq | 2024-06-16

The variables in this problem are the number of small cards (x) and the number of large cards (y). The system of equations is x + y = 25 and 3 x + 5 y = 95 . The student sold 15 small cards and 10 large cards after solving the equations graphically or algebraically.
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Answered by Anonymous | 2024-12-23