If an explosive shell can travel 500 yards in 1.5 seconds, and a shell bursts with a 25-yard diameter of damage, while it takes 3 seconds for the fuse in the shell to go off, what is the farthest distance a target could be hit with the shell?

an e x pl os i v e s h e ll c an t r a v e l 500 y a r d s in 1.5 seco n d s → . → 1000 y a r d s in 3 seco n d s d iam e t er = 25 y a r d s → r a d i u s = 12.5 y a r d s 1000 + 12.5 = 1012.5 [ y a r d s ] A n s w er : T h e f a r t h es t a w a y a t a r g e t co u l d b e hi t w i t h a s h e ll i s 1012.5 y a r d s

Answered by kate200468 | 2024-06-10

The farthest distance a target could be hit with the shell is calculated by adding the time it takes for the shell to travel before exploding (1000 yards) to the blast radius of the explosion (12.5 yards). Therefore, the total distance is 1012.5 yards. This means that if a target were located up to 1012.5 yards away, it could be affected by the shell's explosion.
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Answered by kate200468 | 2024-12-23