The difference between two positive integers is 40. One integer is three times as great as the other. Find the integers.

Be the integers: x and y
x - y = 40 x = 3y
Replace x in the first equation:
3y - y = 40 2y = 40 y = 20 x = 60

Answered by Ryan2 | 2024-06-10

To find the two positive integers where one is three times greater than the other and their difference is 40, solve the equation 3x - x = 40, yielding integers 20 and 60.

The question you've asked involves finding two positive integers given that one is three times as great as the other and their difference is 40. Let's denote the smaller integer as x and the larger integer as 3x, as one is three times greater than the other. According to the problem, the difference between these two integers is 40. We can represent this situation with the equation 3x - x = 40.
Solving this equation:
Combine like terms: 3x - x = 2xDivide both sides by 2 to find x: x = 40 / 2Now, x = 20.
Since the larger integer is three times the smaller one, 3x = 3 * 20 = 60.
Therefore, the two positive integers are 20 and 60.

Answered by SravyaDa | 2024-06-25

The two positive integers are 60 and 20, where 60 is three times as great as 20, and their difference is 40.
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Answered by Ryan2 | 2024-10-10