What is the alpha decay of Radon-198?

86198Rn => 24He + 84194Po
The radon is shown on the left, and the alpha particle, which is a helium nucleus, is shown of the right with the polonium.

Answered by chrissybrackeen | 2024-06-10

The alpha decay of **Radon-198 **produces alpha particle and ¹⁹⁴₈₄Po.

What is alpha decay?
Alpha decay is a type of radioactive disintegration in which some **unstable atomic nuclei **spontaneously expel an alpha particle to dissipate excess energy.
Alpha decay of **Radon-198 **is shown as:
¹⁹⁸₈₆Rn → ⁴₂He + ¹⁹⁴₈₄Po
In the above decay from the parent nuclei , daughter nuclei ( ¹⁹⁴₈₄Po ) and alpha particle ( ⁴₂He ) is produced.
Hence daughter nuclei of the alpha decay of Radon-198 is ¹⁹⁴₈₄Po.

To know more about alpha decay , visit the below link: https://brainly.com/question/13512293
#SPJ2

Answered by nikitarahangdaleVT | 2024-06-16

Radon-198 undergoes alpha decay to produce an alpha particle and Polonium-194. The nuclear equation for this decay is 86 198 ​ R n → 2 4 ​ He + 84 194 ​ P o . This process transforms the unstable Radon-198 into a more stable daughter isotope, Polonium-194.
;

Answered by nikitarahangdaleVT | 2024-09-30