Which of the following have both 2 and -5 as solutions?

A. [tex]x^2 + 3x - 10 = 0[/tex]
B. [tex]x^2 - 3x - 10 = 0[/tex]
C. [tex]x^2 + 7x + 10 = 0[/tex]
D. [tex]x^2 - 7x + 10 = 0[/tex]

x 1 ​ = 2 ; x 2 ​ = − 5 ( x − 2 ) ( x − ( − 5 )) = ( x − 2 ) ( x + 5 ) = x 2 + 5 x − 2 x − 10 = x 2 + 3 x − 10 A n s w er : a .

Answered by Anonymous | 2024-06-10

x 1 ​ = 2 an d x 2 ​ = − 5 ⇒ ( x − x 1 ​ ) ( x − x 2 ​ ) = ( x − 2 ) ( x + 5 ) = x 2 + 5 x − 2 x − 10 = . = x 2 + 3 x − 10 ⇒ A n s . a .

Answered by kate200468 | 2024-06-10

The equation that has both 2 and -5 as solutions is option A: x 2 + 3 x − 10 = 0 . This is derived from expressing the solutions in factored form and expanding it. The other options do not match this equation.
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Answered by Anonymous | 2024-12-20