How do you factor: \( b^2 - 6b + 8 \)?
Answer (2)
This is an easy trinomial. You need to find two numbers that add up to -6 and multiply together to equal 8. Those numbers are -2 and -4. It would simplify to (b-2)(b-4)
To factor the expression b 2 − 6 b + 8 , you need to find two numbers that multiply to 8 and add to -6, which are -2 and -4. This leads to the factored form ( b − 2 ) ( b − 4 ) .
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