n 2 − 5 n + 6 = n 2 − 5 n + 3 n − 3 n + 6 = n 2 − 2 n − 3 n + 6 = = n ( n − 2 ) − 3 ( n − 2 ) = ( n − 2 ) ( n − 3 )
The quadratic expression n 2 − 5 n + 6 can be factored into ( n − 2 ) ( n − 3 ) . This is done by finding two numbers that multiply to 6 and add to -5, which are -2 and -3. We confirm our factorization by expanding it back to the original expression.
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