For the quadratic function [tex]y = (x - 1)^2 + 1[/tex], find the following:

1. Domain
2. Range
3. Vertex
4. Axis of symmetry

y = ( x − 1 ) 2 + 1 F or t h e q u a d r a t i c f u n c t i o n f ( x ) = a ( x − h ) 2 + k w h ere a , h an d k a re re a l n u mb ers w i t h a  = 0 , t h e v er t e x i s ( h , k ) = ( 1 , 1 ) a sy mm e t ry ab o u t t h e v er t i c a l l in e x = h x = 1

Answered by Lilith | 2024-06-10

The domain of the function y = ( x − 1 ) 2 + 1 is all real numbers. The range is from 1 to infinity, the vertex is (1, 1), and the axis of symmetry is x = 1 .
;

Answered by Lilith | 2024-12-23