Find the slope, if it exists, of the line containing the pair of points \((-8, -2)\) and \((-11, -6)\).

delta y = (-6 - -2) = ( -6 + 2) = -4 delta x = ( -11 - -8) = (-11 + 8) = -3 slope is (delta y)/(delta x) = (-4/-3) = 4/3

Answered by Anonymous | 2024-06-10

( − 8 , − 2 ) , ( − 11 , − 6 ) F i rs t f in d t h e s l o p e o f t h e l in e t h r u t h e p o in t s m = x 2 ​ − x 1 ​ y 2 ​ − y 1 ​ ​ m = − 11 − ( − 8 ) − 6 − ( − 2 ) ​ = − 11 + 8 − 6 + 2 ​ = − 3 − 4 ​ = 3 4 ​

Answered by Lilith | 2024-06-10

The slope of the line containing the points (-8, -2) and (-11, -6) is 3 4 ​ . This is calculated using the slope formula, identifying changes in y and x coordinates. Therefore, we conclude that as x changes, y changes roughly 1.33 times that amount.
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Answered by Anonymous | 2025-06-12