Solve the system of equations using substitution:

1. \(4x - 4y = -16\)

2. \(x - 2y = -12\)

\left\{\begin{array}{ccc}4x-4y=-16\\x-2y=-12\end{array}\right\\\\\left\{\begin{array}{ccc}4x-4y=-16\\x=2y-12\end{array}\right\\\\substitution:\\\\4(2y-12)-4y=-16\\8y-48-4y=-16\\4y=-16+48\\4y=32\ \ \ \ /:4\\y=8\\\\x=2\cdot8-12=16-12=4\\\\Solution:x=4\ and\ y=8

Answered by Anonymous | 2024-06-10

By using substitution, we found that the solution to the system of equations is x = 4 and y = 8 . We solved for x in terms of y first, substituted it into the other equation, and simplified to find the values of both variables. This method effectively allows us to solve systems of equations step-by-step.
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Answered by Anonymous | 2025-03-20