300 minuts 5 hours 1.2 killowatt 6 killowatt hour 6*0.15=0.9 $0.9
Data;
Power = 1200W
Time/day = 10 mins
Power
The is the rate of energy used to time . It is the measure of expedience of energy.
a). How many minutes is the dryer used in a month.
Assuming there 30 days in a month;
1 d a y = 10 min s 30 d a ys = x min s x = 30 ∗ 10 x = 300 min s
This shows that the dryer is used 300 minutes in a month.
b). How many hours is the dryer used in a month.
To solve this problem, we simply need to convert the value of (a) from minutes to hours.
1 h r = 60 min s y h r = 300 min s y = 60 300 y = 5 h o u rs
The dryer was used for a total of 5 hours in a month.
c). The power of the dryer in kilowatt.
To convert the power in watt to kilowatt, we divide by 1000.
P = 1200 W P = 1000 1200 P = 1.2 k w
The power in kilowatt is 1.2kw
d). How many kilowatt/hr of electricity used in a month.
1.2 ∗ 5 = 6 k w / h
The dryer consumes 6kw/h in a month.
e). If the town charges $0.15/kwh, the cost in a month
$0.15 = 1 h r x = 6 h r x = 6 ∗ 0.15 x = 0.9
The cost of the dryer in a month is $0.9.
Learn more on power here;
https://brainly.com/question/911620
In a month, the hair dryer is used for 300 minutes or 5 hours. It consumes 6 kilowatt-hours of energy at a cost of $0.90. The power of the dryer is 1.2 kilowatts.
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