A rectangle is 2.5 times as long as it is wide. Find the dimensions of the rectangle if its perimeter is 56 cm.

Question

soniaagarwal09 · Answer

perimeter of a rectangle = 2 (length + breadth) or, 56 = 2(2.5 breadth + breadth) or, 56 = 7 breadth breadth = 56 7 = 8 cm length = 2.5*8 = 20 cm

Anonymous · Answer

The dimensions of the rectangle are 8 cm in width and 20 cm in length. The width was found to be 8 cm, and by using the relation between length and width, the length was calculated to be 20 cm. Together, these dimensions satisfy the stated perimeter of 56 cm. 
 ;

A rectangle is 2.5 times as long as it is wide. Find the dimensions of the rectangle if its perimeter is 56 cm.

Answer (2)

Related Questions in Mathematics

[Done] Select the correct answer. Which equation is equivalent to the given equation? [tex]$x^2-6 x=8$[/tex] A. [tex]$(x-6)^2=44$[/tex] B. [tex]$(x-3)^2=17$[/tex] C. [tex]$(x-6)^2=20$[/tex] D. [tex]$(x-3)^2=14$[/tex]

[Done] Which phrase best describes the translation from the graph [tex]y=6 x^2[/tex] to the graph of [tex]y=6(x+1)^2[/tex]? A. 6 units left B. 6 units right C. 1 unit left D. 1 unit right

[Done] What expression is equivalent to [tex]$\left(5 z^2+3 z+2\right)^2$[/tex] ? A. [tex]$5 z^4+3 z^2+4$[/tex] B. [tex]$5 z^4+9 z^2+4$[/tex] C. [tex]$25 z^4+30 z^3+19 z^2+12 z+4$[/tex] D. [tex]$25 z^4+30 z^3+29 z^2+12 z+4$[/tex]

[Done] The graph of [tex]y=\frac{5}{4} x+1[/tex] is shown below. The coordinate ([tex]0, y[/tex]) is a solution of the equation. Given the [tex]x[/tex]-value of 0, what is the value of the [tex]y[/tex]-coordinate for the coordinate ([tex]0, y[/tex])? [tex]y=[/tex] [blank]

[Done] If [tex]f(-2)=0[/tex], what are all the factors of the function [tex]f(x)=x^3-2 x^2-68 x-120[/tex]? Use the Remainder Theorem. A. [tex](x+2)(x+60)[/tex] B. [tex](x-2)(x-60)[/tex] C. [tex](x-10)(x+2)(x+6)[/tex] D. [tex](x+10)(x-2)(x-6)[/tex]