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In Physics / High School | 2014-05-20

A 60 W light bulb at 120 V is left on in your house to prevent burglary. If the power costs 10 cents per kilowatt-hour, how much will it cost to leave the bulb on for 30 days?

Asked by Smetak155

Answer (2)

4.22 dollars is the cost to leave the bulb on for 30 days.
What is electrical energy?
Electrical energy is the power an atom's charged particles have to cause an action or move an object. The movement of electrons from one atom to another is what results in **electrical energy. **
There is a** dissipation of electrical energy** in the resistor when an electric current flows through it. It depends on the resistance of the resistor and the applied **voltage. **
The expression of the **power dissipation **is as follows ;
P= R V 2 ​
V is the applied voltage.
R is the** resistance.**
Given
P = 60 W
30days * 24h/day = 720 Hours kW * h
Therefore by putting the values in the given formula,
= (60/1000)kW * 720h
= 43.2 kWh
Hence,
The cost is 42.2 kWh42.2 kWh x 0.1
= 4.22 dollars
Learn more about **electrical energy **here:
https://brainly.com/question/1580875
#SPJ2

Answered by snehashish65 | 2024-06-16

It will cost $4.32 to leave a 60 W light bulb on for 30 days at a rate of 10 cents per kilowatt-hour. This was calculated by converting watts to kilowatts, determining the total hours of usage, calculating energy consumption in kilowatt-hours, and then multiplying by the cost per kilowatt-hour.
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Answered by snehashish65 | 2024-09-30